Of Loadlines, Power Output and Distortion
Purpose
In this article we will explore establishing a loadline on a triode vacuum tube (valve), determine the power available from this loadline, and the distortion predicted from this loadline. This will allow the reader a step by step way to calculate the parameters for his design. I have chosen to "invent" a tube for illustrative purposes. My invention is "spec'd" as a triode with the following parameters:
For this article, I will stick with a single ended transformer loaded Class A amplifier, as one of the simplest vehicles that can convey this knowledge. Most of the information is appropriate for push-pull operation, once a composite load line is established (may do that in another article).
Establishing a Load Line
Note that these are all plotted out on the following set of tube curves for our example.
For our example, the data is as follows:
Va= 99V, Vq=300V, Ve=465V, Ia=115mA, Ib=89mA, Ic=65mA, Id=42mA, Ie=23mA. In addition, 40V p-p are required from the driver stage, and a 4k plate transformer is required.
Rectification Effects
In any device with even order distortion (not just second harmonic as sometimes stated), the average current of a Class A stage will change depending on the signal level. If the distortion is relatively low, the effect is relatively unimportant, if the distortion is high, this effect becomes increasingly important. (It is also more important for self bias than fixed bias, as the bias voltage is a function of the average current).
This effect modifies all tube operating characteristics. The degree can be seen by comparing the quiescent current (65 mA in our example) with the average current as taken from the "extremes": that is, (Ia+Ie)/2. In our example that value calculates to 69mA (note that is not substantially different). The effect requires an iterative plot of the load line on the tube characteristics. The "worst case" is shown in "pink" in the constructed load lines above. The real case will be between the two extremes. Notice that the "curve" includes some portion above the maximum dissipation. In this case, the power dissipated in the tube is (300*0.069 - power output), or in this case 16.5 watts. This is still LOWER than the 20 watt max dissipation case, so there's no problem. Note the quiescent dissipation is still 300*0.65, or in this case 19.5 watts.
The remainder of this document ignores this effect: it is important in high distortion cases only, but high distortion cases are not of much interest.
Power Output
Po = (Ve-Va)*(Ve-Va)/(8*loadimpedance).
In our example this is (465-99)*(465-99)/(8*4000)= 4.18 watts. This number is an approximation in that it assumes low distortion.
Second Harmonic Distortion
HD2(%) = 75*(Ia + Ie - 2*Ic)/(Ia + Ib - Id - Ie)
In our example this is 75*(115 + 23 - 2*65)/(115 + 89 - 42 - 23) = 4.3%
Third Harmonic Distortion
HD3(%) = 50*(Ia - (2*Ib) + (2*Id) - Ie)/(Ia + Ib - Id - Ie)
In our example this is 50*(115 - 178 + 84 - 23)/(115 + 89 - 42 - 23) = -0.72%
Notice the minus sign. This indicates that the harmonic content subtracts from the fundamental (flattening it) when the fundamental is at its crest. This *usually* happens on third harmonic distortion in tubes.
Fourth Harmonic Distortion
HD4(%) = 25*(Ia - (4*Ib) + (6*Ic) - (4*Id) + Ie)/(Ia + Ib - Id - Ie)
In our example this is 25*(115 - 356 +390 -168 + 23)/(115 + 89 -42 - 23) = 0.72%
Discussion
If you don't get numbers you like from the above, you are free to choose different operating points and loads to alter the characteristics of the stage. This may alter the distortion, power output or both. You may freely experiment on paper until you get a "design" you like. You can then correlate the results with your own listening tests. Over time, you'll find there is a correlation between what you predict, and what you hear. Then, you will be able to come up with new amplifiers more rapidly, as you will be able to zero in on what you like by doing a few "paper designs" up front, before committing to a particular tube, transformer, or power supply.
This procedure also works for small signal tubes for driver applications, preamps, etc.
Steve